Home Physics Motion in a Straight Line Graph Related Questions The figure shows the velocity-time graph of …
Physics Motion in a Straight Line Graph Related Questions Single Correct MCQ
Published on: September 12, 2026

The figure shows the velocity-time graph of a cyclist who moves along a straight line

tarting with velocity of , and coming to rest at . Choose the incorrect option.

A
Distance traveled by the cyclist is 212.5 m.
B
Distance covered by the cyclist when it moves with constant velocity is 100 m.
C
Velocity of the cyclist at is .
D
Acceleration at is zero,

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Text Solution

Verified by Experts
The correct answer is:
A
To find the correct answer, we will evaluate each option based on the given velocity-time graph.
1. **Calculate the distance**: The distance covered by the cyclist can be found by calculating the area under the velocity-time graph. The graph shows three parts:
  • **From 0 to 10 seconds**, the velocity is increasing from 0 to 10 m/s. The area is a triangle: A1 = \frac{1}{2} \times 10 \times 10 = 50 m.
  • **From 10 to 20 seconds**, the cyclist travels at a constant velocity of 10 m/s. The area is a rectangle: A2 = 10 \times 10 = 100 m.
  • **From 20 to 30 seconds**, the velocity decreases from 10 m/s to 0 m/s. The area is a triangle: A3 = \frac{1}{2} \times 10 \times 10 = 50 m.
Therefore, the total distance = A1 + A2 + A3 = 50 + 100 + 50 = 200 m. Hence, Option A stating the distance is 212.5 m is incorrect.
2. **Evaluate the other options**:
  • **Option B** states the distance covered at a constant velocity (10 m/s) from 10 to 20 seconds is indeed 100 m.
  • **Option C** states the velocity at t = 25s is 5 m/s, which is correct.
  • **Option D** states the acceleration at t = 30s is 0 (since the velocity is constant), which is correct.
Thus, the incorrect statement is in Option A.

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